The terminal velocity (vt) of the spherical rain drop depends on the radius (r) of the spherical rain drop as :
Solution
<p>$6\pi \eta {v_t}r = {4 \over 3}\pi {r^3}(\rho - \sigma )g$</p>
<p>$\Rightarrow {v_t} = C{r^2}$ where C is a constant</p>
<p>or ${v_t} \propto {r^2}$</p>
About this question
Subject: Physics · Chapter: Properties of Solids and Liquids · Topic: Elasticity
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