Medium INTEGER +4 / -1 PYQ · JEE Mains 2022

In an experiment to determine the Young's modulus of wire of a length exactly $1 \mathrm{~m}$, the extension in the length of the wire is measured as $0.4 \mathrm{~mm}$ with an uncertainty of $\pm\, 0.02 \mathrm{~mm}$ when a load of $1 \mathrm{~kg}$ is applied. The diameter of the wire is measured as $0.4 \mathrm{~mm}$ with an uncertainty of $\pm \,0.01 \mathrm{~mm}$. The error in the measurement of Young's modulus $(\Delta \mathrm{Y})$ is found to be $x \times 10^{10}\, \mathrm{Nm}^{-2}$. The value of $x$ is _________________. $\left(\right.$take $\mathrm{g}=10 \mathrm{~ms}^{-2}$ )

Answer (integer) 2

Solution

<p>${{F/A} \over {l/L}} = Y,\,A = \pi {D^2}$</p> <p>$${{\Delta Y} \over Y} = {{\Delta F} \over F} + {{2\Delta D} \over D} + {{\Delta l} \over e} + {{\Delta L} \over L}$$</p> <p>$= 2 \times {{0.01} \over {0.4}} + {{0.02} \over {0.4}}$</p> <p>$= {{0.04} \over {0.4}} = {1 \over {10}}$</p> <p>$Y = {{Fl} \over {A\Delta l}}$</p> <p>$= {{10 \times 1} \over {\pi {{(0.1\,mm)}^2} \times 0.4\,mm}}$</p> <p>$= 1.988 \times {10^{11}}$</p> <p>$\approx 2 \times {10^{11}}$</p> <p>${{\Delta y} \over y} = {1 \over {10}}$</p> <p>$\Delta y = {y \over {10}} = 2 \times {10^{10}}$</p>

About this question

Subject: Physics · Chapter: Properties of Solids and Liquids · Topic: Elasticity

This question is part of PrepWiser's free JEE Main question bank. 183 more solved questions on Properties of Solids and Liquids are available — start with the harder ones if your accuracy is >70%.

Drill 25 more like these. Every day. Free.

PrepWiser turns these solved questions into a daily practice loop. Chapter-wise drills, full mocks, AI doubt chat. No auto-renew.

Start free →