The height of liquid column raised in a capillary tube of certain radius when dipped in liquid A vertically is, $5 \mathrm{~cm}$. If the tube is dipped in a similar manner in another liquid $\mathrm{B}$ of surface tension and density double the values of liquid $\mathrm{A}$, the height of liquid column raised in liquid $\mathrm{B}$ would be __________ m.
Solution
<p>height of capillary rise $= {{2s\cos \theta } \over {\rho gR}}$</p>
<p>When in A 5 cm $= {{2{s_A}\cos \theta } \over {{\rho _A}gR}}$</p>
<p>When in B $h = {{2{s_B}\cos \theta } \over {{\rho _B}gR}}$</p>
<p>${s_B} = 2{s_A}$ and ${\rho _B} = 2{\rho _A}$</p>
<p>$h = {{2 \times 2{s_A} \times \cos \theta } \over {2{\rho _A}gR}} = 5$ cm</p>
About this question
Subject: Physics · Chapter: Properties of Solids and Liquids · Topic: Elasticity
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