"The depth below the surface of sea to which a rubber ball be taken so as to decrease its volume by $0.02 \%$ is _______ $m$. (Take density of sea water $=10^3 \mathrm{kgm}^{-3}$, Bulk modulus of rubber $=9 \times 10^8 \mathrm{~Nm}^{-2}$, and $g=10 \mathrm{~ms}^{-2}$)"

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$$\begin{aligned} & \beta=\frac{-\Delta \mathrm{P}}{\frac{\Delta \mathrm{V}}{\mathrm{V}}} \\ & \Delta \mathrm{P}=-\beta \frac{\Delta \mathrm{V}}{\mathrm{V}} \\ & \rho \mathrm{gh}=-\beta \frac{\Delta \mathrm{V}}{\mathrm{V}} \\ & 10^3 \times 10 \times \mathrm{h}=-9 \times 10^8 \times\left(-\frac{0.02}{100}\right) \\ & \Rightarrow \mathrm{h}=18 \mathrm{~m} \end{aligned}$$

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The depth below the surface of sea to which a rubber ball be taken so as to decrease its volume by $0.02 \%$ is _______ $m$.

(Take density of sea water $=10^3 \mathrm{kgm}^{-3}$, Bulk modulus of rubber $=9 \times 10^8 \mathrm{~Nm}^{-2}$, and $g=10 \mathrm{~ms}^{-2}$)

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The depth below the surface of sea to which a rubber ball be taken so as to decrease its volume by $0.02 \%$ is _______ $m$. (Take density of sea water $=10^3 \mathrm{kgm}^{-3}$, Bulk modulus of rubber $=9 \times 10^8 \mathrm{~Nm}^{-2}$, and $g=10 \mathrm{~ms}^{-2}$)

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More Properties of Solids and Liquids questions

Drill 25 more like these. Every day. Free.

The depth below the surface of sea to which a rubber ball be taken so as to decrease its volume by $0.02 \%$ is _______ $m$.

(Take density of sea water $=10^3 \mathrm{kgm}^{-3}$, Bulk modulus of rubber $=9 \times 10^8 \mathrm{~Nm}^{-2}$, and $g=10 \mathrm{~ms}^{-2}$)