A simple pendulum has a time period of 2 s. What is its length in cm? (Take $g = \pi^2$ m/s²)
Answer (integer)
100
Solution
$T = 2\pi\sqrt{L/g} \Rightarrow L = g(T/2\pi)^2 = \pi^2 \times (1/\pi)^2 = 1$ m = 100 cm
About this question
Subject: Physics · Chapter: Oscillations · Topic: Simple Pendulum
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