A simple pendulum of length $L$ has period $T$. If the length is quadrupled, the new period is:
Solution
$T = 2\pi\sqrt{L/g}$, so $T \propto \sqrt L$. $L \to 4L$ gives $T \to 2T$.
About this question
Subject: Physics · Chapter: Oscillations · Topic: Simple Pendulum
This question is part of PrepWiser's free JEE Main question bank. 15 more solved questions on Oscillations are available — start with the harder ones if your accuracy is >70%.