At displacement $x = A/2$ from mean position in SHM, the ratio KE : PE is:
Solution
$KE = \frac{1}{2}k(A^2-x^2) = \frac{3}{8}kA^2$; $PE = \frac{1}{2}kx^2 = \frac{1}{8}kA^2$. Ratio 3:1.
About this question
Subject: Physics · Chapter: Oscillations · Topic: Energy in SHM
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