Easy MCQ +4 / -1 PYQ · JEE Mains 2022

The aperture of the objective is 24.4 cm. The resolving power of this telescope, if a light of wavelength 2440 $\mathop A\limits^o$ is used to see th object will be :

  1. A 8.1 $\times$ 10<sup>6</sup>
  2. B 10.0 $\times$ 10<sup>7</sup>
  3. C 8.2 $\times$ 10<sup>5</sup> Correct answer
  4. D 1.0 $\times$ 10<sup>$-$8</sup>

Solution

<p>$R.P. = {1 \over {1.22\,\lambda /a}}$</p> <p>$= {{24.4 \times {{10}^{ - 2}}} \over {1.22 \times 2440 \times {{10}^{ - 10}}}}$</p> <p>$= 8.2 \times {10^5}$</p>

About this question

Subject: Physics · Chapter: Optics · Topic: Diffraction and Polarization

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