"Orange light of wavelength 6000 $\times$ 10–10 m illuminates a single slit of width 0.6 $\times$ 10–4 m. The maximum possible number of diffraction minima produced on both sides of the central maximum is ___________."

Question

Accepted Answer

"For minima

$d\,\sin \theta = n\lambda$

or $\sin \theta = {{n\lambda } \over d}$

$\because$ maximum value of sin$\theta$ is 1

$\therefore$ ${{n\lambda } \over d} \le 1$

$n \le {d \over \lambda }$

$n \le {{0.6 \times {{10}^{ - 4}}} \over {6000 \times {{10}^{ - 10}}}}$

$n \le 100$

For both sides 100 + 100 = 200"

Orange light of wavelength 6000 $\times$ 10^–10 m illuminates a single
slit of width 0.6 $\times$ 10^–4 m. The maximum possible number of diffraction minima produced on both sides of the central maximum is ___________.

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Orange light of wavelength 6000 $\times$ 10–10 m illuminates a single slit of width 0.6 $\times$ 10–4 m. The maximum possible number of diffraction minima produced on both sides of the central maximum is ___________.

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Orange light of wavelength 6000 $\times$ 10^–10 m illuminates a single
slit of width 0.6 $\times$ 10^–4 m. The maximum possible number of diffraction minima produced on both sides of the central maximum is ___________.