The critical angle for a medium of refractive index $n$ (with respect to vacuum) is:

1. A $\sin^{-1}(n)$
2. B $\sin^{-1}(1/n)$ Correct answer
3. C $\cos^{-1}(n)$
4. D $\tan^{-1}(n)$

Solution

At critical angle: $n\sin\theta_c = 1 \Rightarrow \theta_c = \sin^{-1}(1/n)$.

About this question

Subject: Physics · Chapter: Optics · Topic: Total Internal Reflection

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