Medium MCQ +4 / -1 PYQ · JEE Mains 2022

The refracting angle of a prism is A and refractive index of the material of the prism is cot (A/2). Then the angle of minimum deviation will be -

  1. A 180 $-$ 2A Correct answer
  2. B 90 $-$ A
  3. C 180 + 2A
  4. D 180 $-$ 3A

Solution

<p>$$\mu = {{\sin \left( {{{{\delta _m} + A} \over 2}} \right)} \over {\sin (A/2)}} = \cot A/2$$</p> <p>$\Rightarrow \cos A/2 = \sin \left( {{{{\delta _m} + A} \over 2}} \right)$</p> <p>$\Rightarrow {\pi \over 2} - {A \over 2} = {{{\delta _m} + A} \over 2}$</p> <p>$\Rightarrow \pi - 2A = {\delta _m}$</p>

About this question

Subject: Physics · Chapter: Optics · Topic: Refraction and Snell's Law

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