The refracting angle of a prism is A and refractive index of the material of the prism is cot (A/2). Then the angle of minimum deviation will be -
Solution
<p>$$\mu = {{\sin \left( {{{{\delta _m} + A} \over 2}} \right)} \over {\sin (A/2)}} = \cot A/2$$</p>
<p>$\Rightarrow \cos A/2 = \sin \left( {{{{\delta _m} + A} \over 2}} \right)$</p>
<p>$\Rightarrow {\pi \over 2} - {A \over 2} = {{{\delta _m} + A} \over 2}$</p>
<p>$\Rightarrow \pi - 2A = {\delta _m}$</p>
About this question
Subject: Physics · Chapter: Optics · Topic: Refraction and Snell's Law
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