In a Young's double slit experiment, the separation between the slits is 0.15 mm. in the experiment, a source of light of wavelengh 589 nm is used and the interference pattern is observed on a screen kept 1.5 m away. The separation between the successive bright fringes on the screen is :
Solution
$$\beta = {{\lambda D} \over d} = {{589 \times {{10}^{ - 9}} \times 1.5} \over {0.15 \times {{10}^{ - 3}}}}$$ = 5.9 mm
About this question
Subject: Physics · Chapter: Optics · Topic: Reflection and Mirrors
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