Easy INTEGER +4 / -1 PYQ · JEE Mains 2020

In a Young's double slit experiment 15 fringes are observed on a small portion of the screen when light of wavelength 500 nm is used. Ten fringes are observed on the same section of the screen when another light source of wavelength $\lambda$ is used. Then the value of $\lambda$ is (in nm) __________.

Answer (integer) 750

Solution

The length of the screen used portion for 15 fringes, and also for ten fringes <br><br>15 $\times$ 500 $\times$ ${D \over \lambda }$ = 10 $\times$ ${{\lambda D} \over \lambda }$ <br><br>$\Rightarrow$ 15 × 50 =$\lambda$ <br><br>$\Rightarrow$ $\lambda$ = 750 nm

About this question

Subject: Physics · Chapter: Optics · Topic: Reflection and Mirrors

This question is part of PrepWiser's free JEE Main question bank. 197 more solved questions on Optics are available — start with the harder ones if your accuracy is >70%.

Drill 25 more like these. Every day. Free.

PrepWiser turns these solved questions into a daily practice loop. Chapter-wise drills, full mocks, AI doubt chat. No auto-renew.

Start free →