Medium MCQ +4 / -1 PYQ · JEE Mains 2022

The interference pattern is obtained with two coherent light sources of intensity ratio 4 : 1. And the ratio ${{{I_{\max }} + {I_{\min }}} \over {{I_{\max }} - {I_{\min }}}}$ is ${5 \over x}$. Then, the value of x will be equal to :

  1. A 3
  2. B 4 Correct answer
  3. C 2
  4. D 1

Solution

<p>$${{{I_{\max }} + {I_{\min }}} \over {{I_{\max }} - {I_{\min }}}} = {{{I_1} + {I_2} + 2\sqrt {{I_1}{I_2}} + {I_1} + {I_2} - 2\sqrt {{I_1}{I_2}} } \over {{I_1} + {I_2} + 2\sqrt {{I_1}{I_2}} - {I_1} - {I_2} + 2\sqrt {{I_1}{I_2}} }}$$</p> <p>$= {{2({I_1} + {I_2})} \over {4\sqrt {{I_1}{I_2}} }}$</p> <p>$$ = {{\left( {{{{I_1}} \over {{I_2}}} + 1} \right)} \over {2\sqrt {{{{I_1}} \over {{I_2}}}} }} = {{4 + 1} \over {2 \times 2}} = {5 \over 4}$$</p> <p>So $x = 4$</p>

About this question

Subject: Physics · Chapter: Optics · Topic: Reflection and Mirrors

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