A ray of light passing through a prism ($\mu$ = $\sqrt 3$) suffers minimum deviation. It is found that the angle of incidence is double the angle of refraction within the prism. Then, the angle of prism is _____________ (in degrees).
Answer (integer)
60
Solution
For minimum deviation r<sub>1</sub> = r<sub>2</sub> = A/2<br><br>given i = 2r<br><br>$\mu = {{\sin i} \over {\sin r}} = {{\sin 2r} \over {\sin r}}$<br><br>$\Rightarrow \cos r = {\mu \over 2}$<br><br>$\Rightarrow$ r = 30$^\circ$<br><br>$\Rightarrow$ A = 60$^\circ$
About this question
Subject: Physics · Chapter: Optics · Topic: Refraction and Snell's Law
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