"The difference of speed of light in the two media A and B (vA $-$ vB) is 2.6 $\times$ 107 m/s. If the refractive index of medium B is 1.47, then the ratio of refractive index of medium B to medium A is : (Given : speed of light in vacuum c = 3 $\times$ 108 ms$-$1)"

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Accepted Answer

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Speed of light in a medium $= {c \over n}$

$\Rightarrow$ According to given information,

${c \over {{n_A}}} - {c \over {{n_B}}} = 2.6 \times {10^7}$

$$ \Rightarrow {{{n_B}} \over {{n_A}}} - 1 = {{2.6 \times {{10}^7}} \over {3 \times {{10}^8}}} \times {n_B}$$

$\Rightarrow {{{n_B}} \over {{n_A}}} \simeq 1.13$

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The difference of speed of light in the two media A and B (v_A $-$ v_B) is 2.6 $\times$ 10⁷ m/s. If the refractive index of medium B is 1.47, then the ratio of refractive index of medium B to medium A is : (Given : speed of light in vacuum c = 3 $\times$ 10⁸ ms^$-$1)

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The difference of speed of light in the two media A and B (vA $-$ vB) is 2.6 $\times$ 107 m/s. If the refractive index of medium B is 1.47, then the ratio of refractive index of medium B to medium A is : (Given : speed of light in vacuum c = 3 $\times$ 108 ms$-$1)

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The difference of speed of light in the two media A and B (v_A $-$ v_B) is 2.6 $\times$ 10⁷ m/s. If the refractive index of medium B is 1.47, then the ratio of refractive index of medium B to medium A is : (Given : speed of light in vacuum c = 3 $\times$ 10⁸ ms^$-$1)