In Young's double slit experiment performed using a monochromatic light of wavelength $\lambda$, when a glass plate ($\mu$ = 1.5) of thickness x$\lambda$ is introduced in the path of the one of the interfering beams, the intensity at the position where the central maximum occurred previously remains unchanged. The value of x will be :
Solution
<p>For the intensity to remain same the position must be of a maxima so path difference must be n$\lambda$ so</p>
<p>(1.5 $-$ 1) x$\lambda$ = n$\lambda$</p>
<p>x = 2n (n = 0, 1, 2 ....)</p>
<p>So, value of x will be</p>
<p>x = 0, 2, 4, 6 ....</p>
About this question
Subject: Physics · Chapter: Optics · Topic: Reflection and Mirrors
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