Medium MCQ +4 / -1 PYQ · JEE Mains 2022

In Young's double slit experiment performed using a monochromatic light of wavelength $\lambda$, when a glass plate ($\mu$ = 1.5) of thickness x$\lambda$ is introduced in the path of the one of the interfering beams, the intensity at the position where the central maximum occurred previously remains unchanged. The value of x will be :

  1. A 3
  2. B 2 Correct answer
  3. C 1.5
  4. D 0.5

Solution

<p>For the intensity to remain same the position must be of a maxima so path difference must be n$\lambda$ so</p> <p>(1.5 $-$ 1) x$\lambda$ = n$\lambda$</p> <p>x = 2n (n = 0, 1, 2 ....)</p> <p>So, value of x will be</p> <p>x = 0, 2, 4, 6 ....</p>

About this question

Subject: Physics · Chapter: Optics · Topic: Reflection and Mirrors

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