With what speed should a galaxy move outward with respect to earth so that the sodium-D line at wavelength 5890 $\mathop A\limits^o$ is observed at 5896 $\mathop A\limits^o$ ?
Solution
$f = {f_0}\sqrt {{{1 + \beta } \over {1 - \beta }}}$<br><br>$\beta = {v \over c}$<br><br>${f \over {{f_0}}} = \sqrt {{{1 + \beta } \over {1 - \beta }}}$<br><br>$${\left( {1 + {{\Delta f} \over {{f_0}}}} \right)^2} = (1 + \beta ){(1 - \beta )^{ - 1}}$$<br><br>$\beta$ is small compared to 1<br><br>$\left( {1 + {{2\Delta f} \over {{f_0}}}} \right) = (1 + 2\beta )$<br><br>$\beta = {{\Delta f} \over {{f_0}}} = {v \over c}$<br><br>$v = 6 \times {c \over {5890}} = 305.6$ km/s
About this question
Subject: Physics · Chapter: Optics · Topic: Reflection and Mirrors
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