Two long current carrying conductors are placed to each other at a distance of 8 cm between them. The magnitude of magnetic field produced at mid-point between the two conductors due to current flowing in them is 300 $\mu$T. The equal current flowing in the two conductors is :
Solution
<p>As B<sub>net</sub> $\ne$ 0 that is the wires are carrying current in opposite direction.</p>
<p>$${{{\mu _0}I \times 2} \over {2\pi (4 \times {{10}^{ - 2}})}} = 30 \times {10^{ - 6}}$$ T</p>
<p>$\Rightarrow I = {{30 \times {{10}^{ - 6}}} \over {{{10}^{ - 6}}}}$ A = 30 A in opposite direction.</p>
About this question
Subject: Physics · Chapter: Magnetic Effects of Current · Topic: Biot-Savart Law
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