A galvanometer coil has 500 turns and each turn has an average area of 3 $\times$ 10–4 m2 . If a torque of 1.5 Nm is required to keep this coil parallel to a magnetic field when a current of 0.5 A is flowing through it, the strength of the field (in T) is ______.
Answer (integer)
20
Solution
Given N = 500
<br><br>A = 3 $\times$ 10<sup>–4</sup> m<sup>2</sup>
<br><br>$\tau$ = 1.5 Nm
<br><br>i = 0.5 A
<br><br>We know, $\tau = BINA\,sin\theta$<br><br>$1.5 = B \times 0.5 \times 500 \times 3 \times {10^{ - 4}}$<br><br>$B = {{10000} \over {500}} = 20$ Tesla
About this question
Subject: Physics · Chapter: Magnetic Effects of Current · Topic: Biot-Savart Law
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