A wire of length $314 \mathrm{~cm}$ carrying current of $14 \mathrm{~A}$ is bent to form a circle. The magnetic moment of the coil is ________ A $-\mathrm{m}^{2}$. [Given $\pi=3.14$]
Answer (integer)
11
Solution
<p>$R = {l \over {2\pi }} = {{314} \over {2 \times 3.14}} = 50$ cm</p>
<p>$\mu = \pi {R^2}i$</p>
<p>$= 14 \times 3.14 \times {(0.5)^2}$</p>
<p>$= 11$ A-m<sup>2</sup></p>
About this question
Subject: Physics · Chapter: Magnetic Effects of Current · Topic: Biot-Savart Law
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