A solenoid of 1000 turns per metre has a core with relative permeability 500. Insulated windings of the solenoid carry an electric current of 5A. The magnetic flux density produced by the solenoid is : (permeability of free space = 4$\pi$ $\times$ 10$-$7 H/m)
Solution
B = $\mu$ n i<br><br>B = $\mu$<sub>r</sub> $\mu$<sub>0</sub> n i<br><br>B = 500 $\times$ 4$\pi$ $\times$ 10<sup>$-$7</sup> $\times$ 10<sup>3</sup> $\times$ 5<br><br>B = $\pi$ $\times$ 10<sup>$-$3</sup> $\times$ 10<sup>3</sup><br><br>B = $\pi$ T
About this question
Subject: Physics · Chapter: Magnetic Effects of Current · Topic: Biot-Savart Law
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