A charged particle carrying charge 1 $\mu$C is moving
with velocity $\left( {2\widehat i + 3\widehat j + 4\widehat k} \right)$ ms–1. If an external
magnetic field of $\left( {5\widehat i + 3\widehat j - 6\widehat k} \right)$× 10–3 T exists in the region where the particle is moving then the
force on the particle is $\overrightarrow F$
× 10–9 N. The vector $\overrightarrow F$
is :
Solution
Given,
<br><br>${\overrightarrow V }$ = $\left( {2\widehat i + 3\widehat j + 4\widehat k} \right)$ ms<sup>–1</sup>
<br><br>${\overrightarrow B }$ = $\left( {5\widehat i + 3\widehat j - 6\widehat k} \right)$× 10<sup>–3</sup> T
<br><br>q = 1 $\mu$C
<br><br>$$\overrightarrow F = q\left( {\overrightarrow V \times \overrightarrow B } \right)$$
<br><br>= $${10^{ - 6}} \times {10^{ - 3}} \times \left| {\matrix{
{\widehat i} & {\widehat j} & {\widehat k} \cr
2 & 3 & 4 \cr
5 & 3 & { - 6} \cr
} } \right|$$
<br><br>= (${ - 30\widehat i + 32\widehat j - 9\widehat k}$) $\times$ 10<sup>-9</sup>
About this question
Subject: Physics · Chapter: Magnetic Effects of Current · Topic: Biot-Savart Law
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