A particle of charge q and mass m is moving with a velocity $- v\widehat i$ (v $\ne$ 0) towards a large screen placed in the Y - Z plane at a distance d. If there is a magnetic field $\overrightarrow B = {B_0}\widehat k$ , the maximum value of v for which the particle will not hit the screen is :
Solution
In uniform magnetic field particle moves in a circular path, if the radius of the circular path is 'd', particle will
not hit the screen.
<br><br>r = ${{mv} \over {q{B_0}}}$
<br><br>To not collide, r < d
<br><br>$\Rightarrow$ ${{mv} \over {q{B_0}}}$ < d
<br><br>$\Rightarrow$ v < ${{q{B_0}d} \over m}$
<br><br>$\therefore$ v<sub>max</sub> = ${{q{B_0}d} \over m}$
About this question
Subject: Physics · Chapter: Magnetic Effects of Current · Topic: Biot-Savart Law
This question is part of PrepWiser's free JEE Main question bank. 96 more solved questions on Magnetic Effects of Current are available — start with the harder ones if your accuracy is >70%.