A wire of length 0.5 m carries 4 A in a 0.2 T field perpendicular to it. The force on the wire is:
Solution
$F = BIL = 0.2\times 4\times 0.5 = 0.4$ N.
About this question
Subject: Physics · Chapter: Magnetic Effects of Current · Topic: Force on Current-Carrying Conductor
This question is part of PrepWiser's free JEE Main question bank. 10 more solved questions on Magnetic Effects of Current are available — start with the harder ones if your accuracy is >70%.