"A deuteron and a proton moving with equal kinetic energy enter into a uniform magnetic field at right angle to the field. If rd and rp are the radii of their circular paths respectively, then the ratio ${{{r_d}} \over {{r_p}}}$ will be $\sqrt{x}$ : 1 where x is __________."

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Accepted Answer

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$R = {{\sqrt {2mK} } \over {qB}}$

So, ${{{r_d}} \over {{r_p}}} = {{\sqrt {{m_d}} /{q_d}} \over {\sqrt {{m_p}} /{q_p}}}$

$= \sqrt 2$

So $x = 2$

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A deuteron and a proton moving with equal kinetic energy enter into a uniform magnetic field at right angle to the field. If r_d and r_p are the radii of their circular paths respectively, then the ratio ${{{r_d}} \over {{r_p}}}$ will be $\sqrt{x}$ : 1 where x is __________.

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A deuteron and a proton moving with equal kinetic energy enter into a uniform magnetic field at right angle to the field. If rd and rp are the radii of their circular paths respectively, then the ratio ${{{r_d}} \over {{r_p}}}$ will be $\sqrt{x}$ : 1 where x is __________.

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A deuteron and a proton moving with equal kinetic energy enter into a uniform magnetic field at right angle to the field. If r_d and r_p are the radii of their circular paths respectively, then the ratio ${{{r_d}} \over {{r_p}}}$ will be $\sqrt{x}$ : 1 where x is __________.