A long solenoid is formed by winding 70 turns cm$^{-1}$. If 2.0 A current flows, then the magnetic field produced inside the solenoid is ____________ ($\mu_0=4\pi\times10^{-7}$ TmA$^{-1}$)
Solution
Number of turns per meter $=7000$ turns per $\mathrm{m}$
<br/><br/>
$$
\begin{aligned}
&i=2 \mathrm{~A} & \\\\
& B=\mu_{0} n i =4 \pi \times 10^{-7} \times 7000 \times 2 \\\\
& =56 \pi \times 10^{-4} \mathrm{~T} \\\\
& =56 \times \frac{22}{7} \times 10^{-4} \mathrm{~T} \\\\
& =176 \times 10^{-4} \mathrm{~T}
\end{aligned}
$$
About this question
Subject: Physics · Chapter: Magnetic Effects of Current · Topic: Biot-Savart Law
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