The current of $5 \mathrm{~A}$ flows in a square loop of sides $1 \mathrm{~m}$ is placed in air. The magnetic field at the centre of the loop is $X \sqrt{2} \times 10^{-7} T$. The value of $X$ is _________.
Answer (integer)
40
Solution
<p>$$\begin{aligned}
& \mathrm{B}=4 \times \frac{\mu_0 \mathrm{i}}{4 \pi(1 / 2)}\left(\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}\right) \\
& =4 \times 10^{-7} \times 5 \times 2 \times \sqrt{2} \\
& -40 \sqrt{2} \times 10^{-7} \mathrm{~T}
\end{aligned}$$</p>
About this question
Subject: Physics · Chapter: Magnetic Effects of Current · Topic: Biot-Savart Law
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