A closely wounded circular coil of radius 5 cm produces a magnetic field of $37.68 \times 10^{-4} \mathrm{~T}$ at its center. The current through the coil is _________A.
[Given, number of turns in the coil is 100 and $\pi=3.14$]
Answer (integer)
3
Solution
<p>$B = {{{\mu _0}nI} \over {2R}}$</p>
<p>$$37.68 \times {10^{ - 4}} = {{4\pi \times {{10}^{ - 7}}100\,I} \over {2 \times 5 \times {{10}^{ - 2}}}}$$</p>
<p>$I = {{300\,A} \over {100}}$</p>
<p>$= 3\,A$</p>
About this question
Subject: Physics · Chapter: Magnetic Effects of Current · Topic: Biot-Savart Law
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