A charge particle is moving in a uniform magnetic field $(2 \hat{i}+3 \hat{j}) \,\mathrm{T}$. If it has an acceleration of $(\alpha \hat{i}-4 \hat{j})\, \mathrm{m} / \mathrm{s}^{2}$, then the value of $\alpha$ will be :
Solution
<p>As magnetic force is perpendicular to magnetic field</p>
<p>So, $\overrightarrow F$ . $\overrightarrow B$ must be 0</p>
<p>So, 2$\alpha$ $-$ 12 = 0</p>
<p>$\alpha$ = 6</p>
About this question
Subject: Physics · Chapter: Magnetic Effects of Current · Topic: Biot-Savart Law
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