A small toy starts moving from the position of rest under a constant acceleration. If it travels a distance of 10m in t s, the distance travelled by the toy in the next t s will be :

<p>A small toy begins to move from a standstill with a constant acceleration. It covers a distance of 10 meters in t seconds. We need to determine the distance the toy will travel in the subsequent t seconds.</p> <p>First, we know that the initial distance traveled is given by the formula for constant acceleration starting from rest:</p> <p>$\frac{1}{2} a t^2 = 10 \text{ m}$</p> <p>Next, we calculate the total distance traveled after 2t seconds:</p> <p>$\frac{1}{2} a (2t)^2 = \frac{1}{2} a \cdot 4t^2 = 2 a t^2$</p> <p>Since we know from the initial condition that $ \frac{1}{2} a t^2 = 10 \text{ m} $, multiplying it by 4 gives</p> <p>$2 a t^2 = 40 \text{ m}$</p> <p>Thus, the additional distance traveled in the next t seconds is:</p> <p>$$\text{Total distance after 2t seconds} - \text{Distance already traveled in t seconds}$$</p> <p>$= 40 \text{ m} - 10 \text{ m}$</p> <p>$= 30 \text{ m}$</p> <p></p>