A car travels a distance of '$x$' with speed $v_1$ and then same distance '$x$' with speed $v_2$ in the same direction. The average speed of the car is :
Solution
$$
\begin{aligned}
& \text { Average velocity }=\frac{\text { Total displacement }}{\text { Total time }} \\\\
& =\frac{\mathrm{x}+\mathrm{x}}{\frac{\mathrm{x}}{\mathrm{v}_1}+\frac{\mathrm{x}}{\mathrm{v}_2}}=\frac{2 \mathrm{v}_1 \mathrm{v}_2}{\mathrm{v}_1+\mathrm{v}_2}
\end{aligned}
$$
About this question
Subject: Physics · Chapter: Kinematics · Topic: Motion in a Straight Line
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