The initial speed of a projectile fired from ground is $\mathrm{u}$. At the highest point during its motion, the speed of projectile is $\frac{\sqrt{3}}{2} u$. The time of flight of the projectile is :
Solution
$u \cos \theta=\frac{\sqrt{3}}{2} u$
<br/><br/>$\Rightarrow$ $\cos \theta=\frac{\sqrt{3}}{2}$
<br/><br/>$\Rightarrow$ $\theta=30^{\circ}$
<br/><br/>Time of flight $=\frac{2 u \sin \theta}{g}=\left(\frac{u}{g}\right)$
About this question
Subject: Physics · Chapter: Kinematics · Topic: Motion in a Straight Line
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