A particle is moving in a straight line such that its velocity is increasing at 5 ms$-$1 per meter. The acceleration of the particle is _____________ ms$-$2 at a point where its velocity is 20 ms$-$1.
Answer (integer)
100
Solution
<p>${{dv} \over {dx}} = 5$ ms<sup>$-$1</sup>/m</p>
<p>Acceleration of particle</p>
<p>when $v = 20$ m/s</p>
<p>$a = v{{dv} \over {dx}} = 20(5)$ m/s<sup>2</sup> = 100 m/s<sup>2</sup></p>
About this question
Subject: Physics · Chapter: Kinematics · Topic: Motion in a Straight Line
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