The distance travelled by a particle is related to time t as $x=4\mathrm{t}^2$. The velocity of the particle at t=5s is :-
Solution
$$
\begin{aligned}
& x=4 t^2 \\\\
& v=\frac{d x}{d t}=8 t
\end{aligned}
$$<br/><br/>
At $\mathrm{t}=5 ~\mathrm{sec}$<br/><br/>
$\mathrm{v}=8 \times 5=40 \mathrm{~m} / \mathrm{s}$
About this question
Subject: Physics · Chapter: Kinematics · Topic: Motion in a Straight Line
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