Train A and train B are running on parallel
tracks in the opposite directions with speeds of
36 km/hour and 72 km/hour, respectively. A
person is walking in train A in the direction
opposite to its motion with a speed of 1.8 km/
hour. Speed (in ms–1) of this person as
observed from train B will be close to :
(take the
distance between the tracks as negligible)
Solution
Velocity of man with respect to ground
<br><br>${\overrightarrow V _{m/g}}$ = ${\overrightarrow V _{m/A}}$ + ${\overrightarrow V _{A}}$
<br><br>= -1.8 + 36
<br><br>Velocity of man w.r.t. B
<br><br>${\overrightarrow V _{m/B}}$ = ${\overrightarrow V _{m}}$ - ${\overrightarrow V _{B}}$
<br><br>= –1.8 + 36 – (–72)
<br><br>= 106.2 km/hr
<br><br>= 29.5 m/s
About this question
Subject: Physics · Chapter: Kinematics · Topic: Motion in a Straight Line
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