If Earth's mass were doubled and its radius halved, the escape velocity would become $k$ times the original. Find $k$.
Answer (integer)
2
Solution
$v_e \propto \sqrt{M/R}$. New / old = $\sqrt{(2M)/(R/2) \div (M/R)} = \sqrt{4} = 2$.
About this question
Subject: Physics · Chapter: Gravitation · Topic: Escape Velocity
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