Easy MCQ +4 / -1 PYQ · JEE Mains 2022

Light wave travelling in air along x-direction is given by ${E_y} = 540\sin \pi \times {10^4}(x - ct)\,V{m^{ - 1}}$. Then, the peak value of magnetic field of wave will be (Given c = 3 $\times$ 10⁸ ms^$-$1)

A 18 $\times$ 10$-$7 T Correct answer
B 54 $\times$ 10$-$7 T
C 54 $\times$ 10$-$8 T
D 18 $\times$ 10$-$8 T

Solution

$c = 3 \times {10^8}$ m/sec $B = {E \over c} = {{540} \over {3 \times {{10}^8}}} = 18 \times {10^{ - 7}}\,T$

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Subject: Physics · Chapter: Electromagnetic Waves · Topic: Properties of EM Waves

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Light wave travelling in air along x-direction is given by ${E_y} = 540\sin \pi \times {10^4}(x - ct)\,V{m^{ - 1}}$. Then, the peak value of magnetic field of wave will be (Given c = 3 $\times$ 108 ms$-$1)

Solution

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Light wave travelling in air along x-direction is given by ${E_y} = 540\sin \pi \times {10^4}(x - ct)\,V{m^{ - 1}}$. Then, the peak value of magnetic field of wave will be (Given c = 3 $\times$ 10⁸ ms^$-$1)