An object is placed in a medium of refractive index 3 . An electromagnetic wave of intensity $6 \times 10^8 \mathrm{~W} / \mathrm{m}^2$ falls normally on the object and it is absorbed completely. The radiation pressure on the object would be (speed of light in free space $=3 \times 10^8 \mathrm{~m} / \mathrm{s}$ ) :
Solution
<p>$$\begin{aligned}
& \text { Radiation pressure }=\frac{I}{\mathrm{~V}} \\
& =\frac{\mathrm{I} \cdot \mu}{\mathrm{c}} \\
& =\frac{6 \times 10^8 \times 3}{3 \times 10^8} \\
& =6 \mathrm{~N} / \mathrm{m}^2
\end{aligned}$$</p>
About this question
Subject: Physics · Chapter: Electromagnetic Waves · Topic: Properties of EM Waves
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