Medium MCQ +4 / -1 PYQ · JEE Mains 2021

Electric field of plane electromagnetic wave propagating through a non-magnetic medium is given by

E = 20cos(2 $\times$ 1010 t $-$ 200x) V/m. The dielectric constant of the medium is equal to : (Take $\mu$r = 1)

  1. A 9 Correct answer
  2. B 2
  3. C ${1 \over 3}$
  4. D 3

Solution

Given, electric field,<br/><br/>E = 20 cos(2 $\times$ 10<sup>10</sup>t $-$ 200 x) V/m<br/><br/>Comparing with the standard equation,<br/><br/>E = E<sub>0</sub> cos($\omega$t $-$ kx) V/m, we get<br/><br/>Wave constant, k = 200<br/><br/>Angular frequency, $\omega$ = 2 $\times$ 10<sup>10</sup> rad/s<br/><br/>Speed of the wave, $v = {\omega \over k} = {{2 \times {{10}^{10}}} \over {200}} = {10^8}$ m/s<br/><br/>Refractive index, $\mu = {c \over v} = {{3 \times {{10}^8}} \over {{{10}^8}}} = 3$<br/><br/>As we know the relation between the refractive index and dielectric constant,<br/><br/>$\mu = \sqrt {{\varepsilon _r}{\mu _r}}$<br/><br/>Substituting the value in the above equations, we get<br/><br/>$3 = \sqrt {{\varepsilon _r}(1)}$<br/><br/>${\varepsilon _r} = 9$<br/><br/>Thus, the dielectric constant of the medium is 9.

About this question

Subject: Physics · Chapter: Electromagnetic Waves · Topic: Properties of EM Waves

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