The relative permittivity of distilled water is 81. The velocity of light in it will be :
(Given $\mu$r = 1)
Solution
<p>The speed of light in a medium is given by the equation:</p>
<p>$v = \frac{c}{\sqrt{\varepsilon_r \mu_r}}$</p>
<p>where:</p>
<ul>
<li>$c$ is the speed of light in vacuum (approximately $3 \times 10^8$ m/s),</li>
<li>$\varepsilon_r$ is the relative permittivity of the medium (in this case, distilled water, and is given as 81),</li>
<li>$\mu_r$ is the relative permeability of the medium (given as 1 for distilled water).</li>
</ul>
<p>Substituting the given values into the equation, we get:</p>
<p>$v = \frac{3 \times 10^8 \, \text{m/s}}{\sqrt{81 \times 1}}$</p>
<p>$v = \frac{3 \times 10^8 \, \text{m/s}}{9}$</p>
<p>$v = 3.33 \times 10^7 \, \text{m/s}$</p>
<p>So, the speed of light in distilled water is $3.33 \times 10^7$ m/s. </p>
About this question
Subject: Physics · Chapter: Electromagnetic Waves · Topic: Properties of EM Waves
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