The ratio of average electric energy density and total average energy density of electromagnetic wave is :
Solution
Avg electric energy density $=\frac{1}{4} \varepsilon_0 \mathrm{E}_0^2$
<br/><br/>Total Avg energy density $=\frac{1}{2} \varepsilon_0 \mathrm{E}_0^2$
<br/><br/>$\therefore$ Ratio of average electric energy density and total Avg energy density
<br/><br/>$$
= \frac{\frac{1}{4} \varepsilon_0 \mathrm{E}_0^2}{\frac{1}{2} \varepsilon_0 \mathrm{E}_0^2}=\frac{2}{4}=\frac{1}{2}
$$
About this question
Subject: Physics · Chapter: Electromagnetic Waves · Topic: Properties of EM Waves
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