The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by
$\mathrm{{E_x} = {E_o}\sin (kz - \omega t)}$
$\mathrm{{B_y} = {B_o}\sin (kz - \omega t)}$
Then the correct relation between E$_0$ and B$_0$ is given by
Solution
$E_{x}=E_{0} \sin (k z-\omega t)$
<br/><br/>
$B_{y}=B_{0} \sin (k z-\omega t)$
<br/><br/>
$\because$ Velocity $=\frac{E_{0}}{B_{0}}$
<br/><br/>
$\frac{\omega}{k}=\frac{E_{0}}{B_{0}}$
<br/><br/>
$\omega B_{0}=k E_{0}$
About this question
Subject: Physics · Chapter: Electromagnetic Waves · Topic: Properties of EM Waves
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