The magnetic field of a plane electromagnetic wave is
$$\overrightarrow B = 3 \times {10^{ - 8}}\sin \left[ {200\pi \left( {y + ct} \right)} \right]\widehat i$$ T
where c = 3 $\times$ 108
ms–1 is the speed of light.
The corresponding electric field is :
Solution
Given, $$\overrightarrow B = 3 \times {10^{ - 8}}\sin \left[ {200\pi \left( {y + ct} \right)} \right]\widehat i$$ T
<br><br>$\therefore$ E<sub>0</sub> = CB<sub>0</sub>
<br><br>= 3 × 10<sup>8</sup>
× 3 × 10<sup>–8</sup> = 9 V/m
<br><br>We know, $\left( {\overrightarrow E \times \overrightarrow B } \right)||\overrightarrow C$
<br><br>And here $\widehat B = \widehat i\& \widehat C = - \widehat j$
<br><br>$\therefore$ $\widehat E = - \widehat k$
<br><br>So, $$\overrightarrow E = - 9\sin \left[ {200\pi \left( {y + ct} \right)} \right]\widehat k$$ V/m
About this question
Subject: Physics · Chapter: Electromagnetic Waves · Topic: Maxwell's Equations
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