A plane electromagnetic wave of frequency 25 GHz is propagating in vacuum along the z-direction. At a particular point in space and time, the magnetic field is given by $\overrightarrow B = 5 \times {10^{ - 8}}\widehat jT$. The corresponding electric field $\overrightarrow E$ is (speed of light c = 3 × 108 ms–1)
Solution
$\overrightarrow E = \overrightarrow B \times \overrightarrow V$
<br><br>= $$\left( {5 \times {0^{ - 8}}\widehat j} \right) \times \left( {3 \times {{10}^8}\widehat k} \right)$$
<br><br>= ${15\,\widehat i}$ V/m
About this question
Subject: Physics · Chapter: Electromagnetic Waves · Topic: Properties of EM Waves
This question is part of PrepWiser's free JEE Main question bank. 109 more solved questions on Electromagnetic Waves are available — start with the harder ones if your accuracy is >70%.