Easy MCQ +4 / -1

A rod of length $L$ moves with velocity $v$ perpendicular to a field $B$. The motional EMF induced is:

  1. A $BLv$ Correct answer
  2. B $BL/v$
  3. C $B/(Lv)$
  4. D $BLv^2$

Solution

$\varepsilon = BLv$ when $\vec v \perp \vec B \perp \vec L$.

About this question

Subject: Physics · Chapter: Electromagnetic Induction · Topic: Motional EMF

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