A particle is travelling 4 time as fast as an electron. Assuming the ratio of de-Broglie wavelength of a particle to that of electron is 2 : 1, the mass of the particle is :
Solution
$\lambda = {h \over p}$<br><br>$${{{\lambda _p}} \over {{\lambda _e}}} = {{{p_e}} \over {{p_p}}} = {{{m_e}{v_e}} \over {{m_p}{v_p}}}$$<br><br>$2 = {{{m_e}} \over {{m_p}}}\left( {{{{v_e}} \over {4{v_e}}}} \right)$<br><br>$\therefore$ ${m_p} = {{{m_e}} \over 8}$
About this question
Subject: Physics · Chapter: Dual Nature of Matter and Radiation · Topic: de Broglie Hypothesis
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