Two sources of light emit with a power of $200 \mathrm{~W}$. The ratio of number of photons of visible light emitted by each source having wavelengths $300 \mathrm{~nm}$ and $500 \mathrm{~nm}$ respectively, will be :
Solution
<p>$$\begin{aligned}
& \mathrm{n}_1 \times \frac{\mathrm{hc}}{\lambda_1}=200 \\
& \mathrm{n}_2 \times \frac{\mathrm{hc}}{\lambda_2}=200 \\
& \frac{\mathrm{n}_1}{\mathrm{n}_2}=\frac{\lambda_1}{\lambda_2}=\frac{300}{500} \\
& \frac{\mathrm{n}_1}{\mathrm{n}_2}=\frac{3}{5}
\end{aligned}$$</p>
About this question
Subject: Physics · Chapter: Dual Nature of Matter and Radiation · Topic: Photoelectric Effect
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