Easy MCQ +4 / -1 PYQ · JEE Mains 2024

If the total energy transferred to a surface in time $\mathrm{t}$ is $6.48 \times 10^5 \mathrm{~J}$, then the magnitude of the total momentum delivered to this surface for complete absorption will be:

  1. A $2.16 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}$ Correct answer
  2. B $2.46 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}$
  3. C $1.58 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}$
  4. D $4.32 \times 10^{-3} \mathrm{~kg} \mathrm{~m} / \mathrm{s}$

Solution

<p>$$\mathrm{p=\frac{E}{C}=\frac{6.48 \times 10^5}{3 \times 10^8}=2.16 \times 10^{-3}}$$</p>

About this question

Subject: Physics · Chapter: Dual Nature of Matter and Radiation · Topic: de Broglie Hypothesis

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