If the two metals $\mathrm{A}$ and $\mathrm{B}$ are exposed to radiation of wavelength $350 \mathrm{~nm}$. The work functions of metals $\mathrm{A}$ and $\mathrm{B}$ are $4.8 \mathrm{eV}$ and $2.2 \mathrm{eV}$. Then choose the correct option.
Solution
$\phi=\frac{h c}{\lambda}=\frac{1240}{350} \mathrm{eV}=3.54 \mathrm{eV}$
<br/><br/>$\therefore$ Only metal B will emit photoelectron.
About this question
Subject: Physics · Chapter: Dual Nature of Matter and Radiation · Topic: Photoelectric Effect
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